Question

4X ao quadrado-4x+1=4

Answer 1

$4x^{2}$-4x+1=4
$4x^{2}$-4x+1-4=0
$4x^{2}$-4x-3=0
Δ=$b^{2} -4*a*c$
Δ=$(-4)^{2} -4*4*(-3)$
Δ=16+48=64

$x= \frac{-(-4)+- \sqrt{64} }{2*4}$
$x=\frac{4+-8}{8}$
$x1= \frac{4+8}{8} = \frac{12}{8} = \frac{3}{2}$ simplificamos 
$x2= \frac{4-8}{8}= \frac{-4}{8} = -\frac{1}{4}$ simpliicamos