Question

4x ao quadrado - 20x +25

Answer 1

4x² + 20x + 25 = 0
Δ = b² - 4ac
Δ = 20² - 4.4.25
Δ = 400 - 400
Δ = 0

x = (-b ± √Δ) / 2a
x = (20 ± √0) / 2.4
x = 20/8
x = 2,5

Answer 2

4x²-20x+25
Δ= (-20)² - 4×4×25
Δ= 400 - 16×25
Δ= 400-400
Δ=0
x= $\frac{20+- \sqrt{0} }{2*8}$
x=$\frac{20}{8}$
x= 2,5