Question

4x-2x+1=0
me ajudem aí por favor

Answer 1

$4x - x^{2} + 1 = 0$

Δ$= b^{2} - 4.a.c$

Δ$= 4^{2} - 4 . (-1). 1$

Δ$= 16 + 4$

Δ$= 20$

$x1 = \frac{-b + \sqrt{delta} }{2.a}$

$x1 = \frac{-4 + \sqrt{20} }{2.(-1)}$

$x1 = \frac{-4 +2 \sqrt{5} }{-2}$

$x1 = -\frac{(-4 + 2 \sqrt{5}) }{2}$

$x1 = \frac{4 - 2 \sqrt{5} }{2}$

$x1 = 2 - \sqrt{5}$

$x2 = \frac{-b - \sqrt{delta} }{2.a}$

$x2 = \frac{-4 - \sqrt{20} }{2.(-1)}$

$x2 = \frac{-4 - 2 \sqrt{5} }{-2}$

$x2 = - \frac{(-4 - 2 \sqrt{5}) }{2}$

$x2 = \frac{4 + 2 \sqrt{5}}{2}$

$x2 = 2 + \sqrt{5}$

Answer 2

4x-2x+1=0
Δ= (-2)²-4.1.(-4) 
Δ= 4+16 
Δ= 20 
2+2√5/8= 1+√5/4 
2-2√5/8= 1-√5/4