Question

4x^2+28x+49=1
formula de bhaskara

Answer 1

Resposta:

x= -4 ou x= -3

Explicação passo-a-passo:

4x²+28x+49=1

4x²+28x+49-1=0

4x²+28x+48=0      (÷4)

x²+7x+12=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+7x+12=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=7~e~c=12\\\\\Delta=(b)^{2}-4(a)(c)=(7)^{2}-4(1)(12)=49-(48)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(7)-\sqrt{1}}{2(1)}=\frac{-7-1}{2}=\frac{-8}{2}=-4\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(7)+\sqrt{1}}{2(1)}=\frac{-7+1}{2}=\frac{-6}{2}=-3\\\\S=\{-4,~-3\}$