Question

4n ao quadrado - 1
4 primeiros termos.

Answer 1

$\mathsf{a_{n}=4{n}^{2}-1}$

$\mathsf{a_{1}=4.{1}^{2}-1=4-1=3}$

$\mathsf{a_{2}=4.{2}^{2}-1=16-1=15}$

$\mathsf{a_{3}=4.{3}^{2}-1=4.9-1=36-1=37}$

$\mathsf{a_{4}=4.{4}^{2}-1=4.16-1=64-1=65}$