Question

4a/1 - 1a/2 + 5/1 - 1/3= (mmc) me ajudem pfv​

Answer 1

Resposta:

Explicação passo-a-passo:

MMC(1,2,1,3)=MMC(1,1,2,3)=MMC(1,2,3)

1, 2, 3 | 2

1, 1, 3 | 3

1, 1, 1 | 1

MMC = 2 . 3 = 6

4a/1 - 1a/2 + 5/1 - 1/3 =

[(6÷1)*4a-(6÷2)*1a+(6÷1)*5-(6÷3)*1]/6=

[6*4a-3*1a+6*5-2*1]/6=

[24a-3a+30-2]/6=

[21a+28]/6