Question

49 + 14x + x
ao quadrado

Answer 1

49 + 14x + x²

x² + 14x + 49 = 0

Δ = b²-4ac

Δ = 14² - 4.1.49

Δ = 196 - 196

Δ = 0

x = -b ± $\sqrt{}$Δ/2

x = -14 ± 0

x1 = -14 + 0/2 = -14/2 = -7

x2 = -14 - 0/2 = -14/2 = -7

Answer 2

Oi

x² + 14x + 49 = 0

a=1

b=14

c=49

Calculando o Δ

Δ = b2 - 4.a.c

Δ = 142 - 4 . 1 . 49

Δ = 196 - 4. 1 . 49

Δ = 0

Há 1 raiz real.

Aplicando Bhaskara:

Neste caso, x' = x'':

x = (-b +- √Δ)/2a

x' = (-14 + √0)/2.1

x' = - 14 / 2

x' = -7

x'' = (-14 - √0)/2.1

x'' = - 14 / 2

x'' = -7

S= {x' = - 7 e x" = - 7}

Espero ter ajudado