Question

-4²+(3-5).(-2)³+3²-(-2)² =

Answer 1

-4²+(3-5).(-2)³+3²-(-2)²=

-16+(-2).(-8)+9-(+4)=

-16+(+16)+9-4=

-16+16+9-4=

+9-4=
+5

$\frac{2^0-(-2)^2}{2^2+(-2)^3} = \frac{1-(4)}{4+(-8)} = \frac{1-4}{4-8} = \frac{-3}{-4} = \frac{3}{4}$