Question

{[(4²+2x3²)+(16:8)²-35]²+1^10-10^0}+6²-7 = ?

Answer 1

$\{[(4^{2}+2\cdot 3^{2})+(16:8)^{2}-35]^{2}+1^{10}-10^{0}\}+6^{2}-7=\\ \\ \{[(16+2\cdot 9)+2^{2}-35]^{2}+1-1\}+36-7=\\ \\ \{[(16+18)+4-35]^{2}\ +\not 1\ -\not 1\}+29=\\ \\ \{[34+4-35]^{2}\}+29=\\ \\ \{3^{2}\}+29=\\ \\ 9+29=38$