Question

42 – { 18 + [3 ( 7- 3 + 2) + 1] - 4} + 13

Answer 1

Explicação passo-a-passo:

x2+2bx+b2−ba2−2ba−b=0

(1)⋅x2+(2b)⋅x+(b2−ba2−2ba−b)=0

x=−(2b)±(2b)2−4⋅(b2−ba2−2ba−b)−−−−−−−−−−−−−−−−−−−−−−−−√2

x=−2b±4b2−(4b2−4ba2−8ba−4b)−−−−−−−−−−−−−−−−−−−−−−−√2

x=−2b±4ba2+8ba+4b−−−−−−−−−−−−−√2

x=−2b±(2a+2)⋅b√2

x=(2)⋅[(−b)±(a+1)⋅b√](2)

x1=−b+(a+1)⋅b√

x2=−b−(a+1)⋅b√

Answer 2

Resposta:

22

Explicação passo a passo:

42 – { 18 + [3 ( 7- 3 + 2) + 1] - 4} + 13

42 – { 18 + [3 (6) + 1] - 4} + 13

42 – { 18 + 18 + 1] - 4} + 13

42 – { 18 + 19] - 4} + 13

42 – 33 + 13

9+13=

22