Question

4 y ao quadrado + 20 Y + 25 = 0​

Answer 1

Resposta:

$4 {y}^{2} + 20y + 25 = 0 \\ dela = {20}^{2} - 4 \times 4 \times 25 \\ 400 - 400 = 0 \\ x = \frac{ - ( + 20) + ou - \sqrt{0} }{2 \times 4} \\ x = \frac{ - 20}{8} \\ x = \frac{ - 20 \div 4}{8 \div 4} \\ x = \frac{ - 5}{2}$