Question

√4^x+1=³√16 Equação exponencial

Answer 1

√4^x+1=³√16
$\sqrt{ 4^{x+1} } = \sqrt[3]{16}$
$4^{ \frac{1}{x+1} } = \sqrt[3]{ 4^{2} }$
$4^{ \frac{1}{x+1} } = 4^{ \frac{2}{3} }$
$\frac{1}{x+1} = \frac{2}{3}$
2x+2=3
2x=3-2
2x=1
x=1/2