Question

4 - Sendo a =(+2^2)^3 b =(+8)^2. e c=(+16)^-3,Calcule a.b.c

Answer 1

Resposta:

1

Explicação passo-a-passo:

a = (2²)³ = $2^{2.3}$ = $2^{6}$ = 64

b) (8)² = 8 . 8 = 64

c) (16) -³ = $(\frac{1}{16}) ^{3\\} = \frac{1}{4096}$

Calcule a.b.c

64 . 64 . $\frac{1}{4096}$ = $\frac{4096}{4096}$ = 1