Question

4) Resolva as expressões com potências

a)5²+2³-2(3+9=

b)6³:3²+4.10-12=

c)4²-10+(2³-5)=

d)30-(2+1)+2³=​

Answer 1

Resposta:

$\sf{segue \: abaixo \: a \: resposta}$

Explicação passo-a-passo:

a)

$\sf{5²+2³-2(3+9)}$

$\sf{25 + {2}^{3} - 2( 3 + 9) }$

$\sf{25 + 8 - 2( 3 + 9)}$

$\sf{25 + 8 - 2x12}$

$\sf{2x12 = 24}$

$\sf{25 + 8 - 24}$

$\boxed{\boxed{\sf{9}}}$

b)

$\sf{6³:3²+4.10-12}$

$\sf{ \frac{ {6}^{3} }{ {3}^{2} } + 4x10 - 12 }$

$\sf{ \frac{ {6}^{3} }{ {3}^{2} } + 40 - 12 }$

$\sf{ \frac{2 {}^{3}x {3}^{3} }{ {3}^{2} } } + 40 - 12$

$\sf{ {2}^{3} x3 + 40 - 12}$

$\sf{8x3 + 40 - 12}$

$\sf{24 + 40 - 12 = }$

$\boxed{\boxed{\sf{52}}}$

c)

$\sf{4²-10+(2³-5)}$

$\sf{4 {}^{2} = 16 }$

$\sf{16 - 10 + ( {2}^{3} - 5) }$

$\sf{16 - 10 + (8 - 5)}$

$\sf{1 6 - 10 + 3 = }$

$\boxed{\boxed{\sf{9}}}$

d)

$\sf{30-(2+1)+2³}$

$\sf{30 - 3 + {2}^{3} }$

$\sf{ {2}^{3 } = 8}$

$\sf{30 - 3 + 8}$

$\boxed{\boxed{\sf{35}}}$

Answer 2

a)

5²+2³-2(3+9)}5²+2³−2(3+9)

{25 + {2}^{3} - 2( 3 + 9) }25+2

3

−2(3+9)

\{25 + 8 - 2( 3 + 9)}25+8−2(3+9)

\{25 + 8 - 2x12}25+8−2x12

\sf{2x12 = 24}2x12=24

{25 + 8 - 24}25+8−24

b)

{6³:3²+4.10-12}6³:3²+4.10−12

\{ \frac{ {6}^{3} }{ {3}^{2} } + 4x10 - 12 }

3

2

6

3

+4x10−12

{ {6}^{3} }{ {3}^{2} } + 40 - 12 }

3

2

6

3

+40−12

{}^{3}x {3}^{3} }{ {3}^{2} } } + 40 - 12

3

2

2

3

x3

3

+40−12

\{ {2}^{3} x3 + 40 - 12}2

3

x3+40−12

\f{8x3 + 40 - 12}8x3+40−12

\sf{24 + 40 - 12 = }24+40−12=

\boxed{\boxed{\sf{52}}}

52

c)

\sf{4²-10+(2³-5)}4²−10+(2³−5)

\sf{4 {}^{2} = 16 }4

2

=16

\sf{16 - 10 + ( {2}^{3} - 5) }16−10+(2

3

−5)

\sf{16 - 10 + (8 - 5)}16−10+(8−5)

\sf{1 6 - 10 + 3 = }16−10+3=

\boxed{\boxed{\sf{9}}}

9

d)

\sf{30-(2+1)+2³}30−(2+1)+2³

\sf{30 - 3 + {2}^{3} }30−3+2

3

\sf{ {2}^{3 } = 8}2

3

=8

\sf{30 - 3 + 8}30−3+8

\boxed{\boxed{\sf{35}}}

35