Question

4- Resolva abaixo, a equação: x2 + 8x – 9 = 0, pela fórmula resolutiva de Bhaskara.​

Answer 1

• $\boxed{\small{x^{2}+8x-9=0}}$

☑️ Coeficientes

• $\small{a=1}$

• $\small{b=8}$

• $\small{c=-9}$

☑️ Discriminante

• $\small{\Delta=b^{2}-4.a.c}$

• $\small{\Delta=(8)^{2}-4.(1).(-9)}$

• $\small{\Delta=64+36}$

• $\small{\Delta=100}$

☑️ Encontrar as raízes

• $\small{x'=\dfrac{[-(8)+\sqrt{100}]}{2.(1)}}$

• $\small{x'=\dfrac{[-8+10]}{2}}$

• $\small{x'=\dfrac{2}{2}}$

• $\small{x'=1}$

========================================

• $\small{x"=\dfrac{[-(8)-\sqrt{100}]}{2.(1)}}$

• $\small{x"=\dfrac{[-8-10]}{2}}$

• $\small{x"=\dfrac{-18}{2}}$

• $\small{x"=-9}$

☑️ A solução será ={ -9 ; 1}

Answer 2

Resposta:

Explicação passo-a-passo:

x² + 8x – 9 = 0

Δ=b²-4ac => Δ=(8)²-4(1)(-9) => Δ= 64 + 36 =>Δ= 100

x = -b ± √Δ/2a=> x = - 8 ± √100/2(1)=> x = - 8 ± 10/2=>$x_{1}= \frac{-8 + 10 }{2} => x_{1}= \frac{ +2 }{2} => x_{1}= 1\\x_{2}= \frac{-8 - 10 }{2} => x_{2}= \frac{ -18 }{2} => x_{2}= -9$