Question

4) Resolva a equação log (3x -1) + log 2 = log 10.

Answer 1

$log(3x - 1) + log2 = log10\\log[(3x - 1) . 2] = 1\\log(6x - 2) = 1\\6x -2 = 10^{1} \\6x = 10 + 2\\6x = 12\\x = 12 / 6\\x = 2$