Question

4 O valor do lim x 2 x^3 - x^2 - 2x / x^2 – 3x + 2 é

Answer 1

$\lim_{x \to 2} \frac{x^3-x^2-2x}{x^2-3x+2}= \lim_{x \to 2} \frac{x(x^2-x-2)}{x^2-3x+2}= \lim_{x \to 2} \frac{x(x-2)(x+1)}{(x-2)(x-1)}=$ $\lim_{x \to 2} \frac{x(x+1)}{(x-1)}=\frac{2(2+1)}{(2-1)}=\frac{2(3)}{1}=\boxed{6}$