Question

4 numeros consecutivos pares vale 84 quais sao esses numeros

Answer 1

$x+(x+2)+(x+4)+(x+6)=84\\4x+12=84\\4x+12-12=84-12\\4x=72\\\frac{4x}{4}=\frac{72}{4} \\ x = 18   \\x+2=20 \\x+4=22 \\x+6=24 \\\\18+20+22+24=84  \\ N [18, 20,22,24]$