Question

(4+i)+(-1-3i)+(-2+i)???
(1-1)^5????

Answer 1

Oiii

a)
$(4+i)+(-1-3i)+(-2+i) 4 + i - 1- 3i - 2 + i (4 - 1 -2) + (i - 3i + i )$

$\boxed{\boxed{1 - i}}$


b)$(1-1)^{5} = 0^{5} = \boxed{\boxed{0}}$