Question

4 elevado a menos 1 mais 10 elevado a menos 2

Answer 1

Olá Karina.

$(4)^{-1}+ (10)^{-2} = \frac{1}{4}+ \frac{1}{100}= \frac{25+1}{100}= \frac{26}{100}= \frac{13}{50}$

Answer 2

Oie, Td Bom?!

$= 4 {}^{ - 1} + 10 {}^{ - 2} = \frac{1}{4} + \frac{1}{100} = \frac{25 + 1}{100} = \frac{26}{100} = \frac{26 \div 2}{100 \div 2} = \frac{13}{50}$

Att. Makaveli1996