Question

4. Determine as coordenadas do vértice da parábola que representa a função dada
dada por y = 14.x2 + 28x + 13​

Answer 1

$y=14x^2+28x+13\ \to\ a=14,\ b=28,\ c=13$

$V(x_V,y_V)=V\bigg(-\dfrac{b}{2a},-\dfrac{b^2-4ac}{4a}\bigg)$

$x_V=-\dfrac{28}{2(14)}=-1\ \therefore\ \boxed{x_V=-1}$

$y_V=-\dfrac{28^2-4(14)(13)}{2(14)}=-\dfrac{56}{28}\ \therefore\ \boxed{y_V=-2}$

$\mathrm{V\acute{e}rtice}\ \to\ \boxed{V(-1,-2)}$