Question

4) Dada a função f(x) = 4x² + 3x + 5, calcule: f(-2), f(-1), f(0) e f( 2 ). alguém pode mim ajuda?​

Answer 1

bom dia !

$\sf \: f(x) = {4x}^{2} + 3x + 5 \\ \sf \: f( - 2) = 4.( { - 2}^{2} ) + 3.( - 2) + 5 \\ \sf \: 4.4 - 6 + 5 \\ \sf \: 16 - 6 + 5 \\ \sf \: 10 + 5 = \orange{15}$

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$\sf \: f(x) = {4x}^{2} + 3x + 5 \\ \sf \: f( - 1) = 4. {( - 1)}^{2} + 3.( - 1) + 5 \\ \sf \: 4. 1 - 3 + 5 \\ \sf \: 4 - 3 + 5 = \orange{ 6}$

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$\sf \: f(x) {4x}^{2} + 3x + 5 \\ \sf \: f(0) = {4.0}^{2} + 3.0 + 5 \\ \sf \: 4.0 + 0 + 5 \\ \sf \: f(0) = \orange{ + 5}$

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$\sf \: f(x) = {4x}^{2} +3 x + 5 \\ \sf \: f(2) = {4.2}^{2} + 3.2 + 5 \\ \sf \: 4.4 + 6 + 5 \\ \sf \: 16 + 11 = \orange{27}$

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