Question

4- Calcule o valor numérico de:
​

Answer 1

Resposta ↓

a) = 4

b) = 4

c) = 196

Explicação passo a passo:

$\sqrt{x^{2} + 4x + 4}, trocamos\ x\ por\ 2\\\\\\\sqrt{2^2 + 4.2 + 4} \\\\\\\sqrt{4 + 8 + 4} \\\\\\\sqrt{16} = 4\\\\\\a) = 4\\\\\\\cfrac{m^2 - 5n}{5m + n^2}, trocamos\ m\ por\ -1\ e\ n\ por\ -3\\\\\\\cfrac{(-1)^2 - 5.(-3)}{5.(-1) + (-3)^2} \\\\\\\cfrac{1 + 15}{- 5 + 9 } \\\\\\\cfrac{16}{4} \\\\\\b) = 4\\\\\\(2t + 1)^2 . (t + 1), trocamos\ t\ por\ 3:\\\\\\(2.3 + 1)^2 . (3 + 1)\\\\\\(7)^2 . (4)\\\\\\49 . 4\\\\\\c) = 196$

Answer 2

Resposta:

A) 4   B) 4 C) 196

Explicação passo-a-passo:

a)

$\sqrt[]{2^{2}+4*2+4 }\\\\\sqrt{(2+2)^{2} } \\\\2+2=4$

b)

$\frac{(-1)^{2}-5*(-3) }{5*(-1)+(-3)^{2} } \\\\\frac{1+15}{-5+9}\\\\\frac{16}{4} =4$

c)

$(2*(3)+1)^{2} *(3+1)\\(6+1)^{2} *4\\\\7^{2} *4\\\\49*4\\\\196$