Question

4) Adotando log 611=1,34 e log6 2=0,39 , calcule :
a) log6 16 = b) log6 22 = c) log644=

Answer 1

Resposta:

Sabendo que $\log_x y\times z=\log_x y + \log_x z$ , então:

A.

$\log_6 16 = \\\log_6 2^4 = \\\log_6 (2\times 2\times 2\times 2)=\\\log_6 2+\log_6 2+\log_6 2+\log_6 2 =\\0,39+0,39+0,39+0,39=\\1,56$

B.

$\log_6 22 =\\\log_6 (11\times2) =\\\log_6 11 + \log_6 2 =\\1,34+0,39=\\1,73$

C.

$\log_6 44 =\\\log_6 (11\times2\times2) =\\\log_6 11 + \log_6 2 +\log_6 2 =\\1,34+0,39+0,39=\\2,12$