Question

(4-4/5)÷(9+1/3) ....

Answer 1

$(4-\frac{4}{5}) \div (9+\frac{1}{3})=\\ \\ \frac{20-4}{5} \div \frac{27+1}{3}=\\ \\ \frac{16}{5} \div \frac{28}{3}=\\ \\ \frac{16}{5}*\frac{3}{28}=\frac{12}{35}$