Question

4/3+3/8+2/5=

tem aver com MMC ajudem por favor​

Answer 1

$\large\boxed{\begin{array}{l}\sf Como\,Somar\,Frac_{\!\!,}\tilde{o}es\,com\,Denominadores\,Diferentes\\\sf Para\,resolver\,essa\,express\tilde{a}o \,com\,soma\,de\,frac_{\!\!,}\tilde{o}es\\\sf com\,denominadores\,diferentes,calculo\,o\,mmc\,dos\\\sf denominador\,para\,reduzir\,as\,frac_{\!\!,}\tilde{o}es\,ao\,mesmo\\\sf denominador.\,Depois,com\,os\,denominadores\,iguais\\\sf\acute{e}\,s\acute{o}\,repetir\,o\,denominador\,e\,soma\,os \,numeradores.\end{array}}$

$\large\boxed{\begin{array}{l}\sf\dfrac{4}{3}+\dfrac{3}{8}+\dfrac{2}{5}\\\\\begin{array}{c|c}\sf3,8,5&\sf2\\\sf3,4,5&\sf2\\\sf3,2,5&\sf2\\\sf3,1,5&\sf3\\\sf1,1,5&\sf5\\\sf1,1,1\end{array}\\\sf m\cdot m\cdot c(3,8,5)=2\cdot2\cdot2\cdot3\cdot5=120\\\tt\dfrac{4}{3}+\dfrac{3}{8}+\dfrac{2}{5}=\dfrac{160}{120}+\dfrac{45}{120}+\dfrac{48}{120}=\dfrac{253}{120}\end{array}}$