Question

(-4).(-3-1) elevado a 2-[-(8+2) elevado a 2:(3-2)elevado a 2],QUERO A CONTA,a resposta tem que dá 0

Answer 1

$(-4)\times(-3-1)^2-[-(8+2)^2\div(3-2)^2]=\\ (-4)\times(-4)^2-[-(10)^2\div(1)^2]=\\ (-4)\times(+16)-[-(100)\div(1)]=\\ (-64)-[-100]=\\ -64+100=+36$