Question

4 ×+¹=32 qual a solução?

Answer 1

4^x+1 = 32
4^x+1 = 2^5
2^2.(x + 1) = 2^5
2^2x + 2 = 2^5
2x + 2 = 5
2x = 5 - 2
2x = 3
x = 3/2

Answer 2

$\mathtt{4^{x+1} = 32} \\ \mathtt{Fatorando} \\ \\ \mathtt{32 \div 2 } \\ \mathtt{16 \div 2} \\ \mathtt{8 \div 2 } \\ \mathtt{4 \div 2 } \\ \mathtt{2 \div 2} \\ \mathtt{1} \\ \\ \mathtt{4 \div 2 } \\ \mathtt{2 \div 2 } \\ \mathtt{1} \\ \\ \mathtt{2^{2.(x + 1)}} = 2^5} \\ \mathtt{cortantdo ~~2} \\ \\ \mathtt{2.(x+1) = 5} \\ \mathtt{2x + 2 = 5} \\ \mathtt{2x = 5 - 2} \\ \mathtt{2x = 3} \\ \mathtt{x = 3 \div 2} \\ \mathtt{x = 1,5} \\ \\ \\ \boxed{\boxed{\mathtt{Resposta : 1,5}}}$