Question

(4^×)^×-1 = 16 Me ajudem pvfr​

Answer 1

Resposta:

$(4 {}^{x} ) {}^{x - 1} = 16 \\ 4 {}^{x} {}^{(x - 1)} = 16 \\ 4 {}^{x {}^{2} } {}^{ -x } = 4 {}^{2} \\ x {}^{2} - x = 2 \\ x {}^{2} - x - 2 = 0$