Question

3y ao quadrado +4y +1=0​

Answer 1

Resposta:

$S=\{-{1\over3},-1\}$

Explicação passo-a-passo:

3y² + 4y + 1=0

coeficientes

a=3

b=4

c=1

Δ=b²-4ac

Δ=4²-4(3)(1)

Δ=16-12

Δ=4

$x={-b\pm\sqrt{\Delta} \over2a}={-4\pm\sqrt{4} \over2.(3)}={-4\pm2\over6}\\ \\ x'={-4+2\over6}=-{2\over6}=-{1\over3}\\ \\ x"={-4-2\over6}=-{6\over6}=-1$