Question

3y-5(y+1)=3

4y-3(y-5)=15

4y+3(2-y)=6

9x-2(2x+3)=x-6

Answer 1

3y-5(y+1)=3 
3y- 5y - 5 = 3
- 2y - 5 = 3
- 2y = 3 + 5
- 2y = 8
y = 8/-2
y = - 8/2
y = - 4

4y-3(y-5)=15 
4y -3y + 15 = 15
1y + 15 = 15
1y = 15 - 15
1y = 0
y = 0/1
y = 0

4y+3(2-y)=6
4y + 6 - 3y = 6
4y - 3y = 6 - 6
1y = 0
y = 0/1
y = 0


9x-2(2x+3)=x-6
9x - 4x - 6= x - 6

5x - 6 = x - 6
5x - 6 - x = - 6
4x - x = - 6 + 6
3x = 0
x = 0/3
x = 0