Question

(3y+1=y^2-1)/(2 = 3)

Answer 1

(3Y+1)/2=(Y^2-1)/3

-1/3Y^2+1(1/2)Y+5/6=0

Y[1,2]=

{-3/2-( raíz quadrada)(3/2)^2 -4.(-1/3.5/6)/2.(-1/3)-3/2+(raíz quadrada) (3/2)^2-4x(-1/3x5/6)/2.(-1/3)

Y{1,2}={5,-1/2}