Question

-3x² - 2x + 1 = 0
como se faz essa formula de bhaskara?

Answer 1

$-3x^2 - 2x + 1 = 0$

a = -3

b = -2

c = 1

$\Delta = b^2 - 4ac\\\Delta = (-2)^2 - 4 \cdot (-3) \cdot 1\\\Delta = 4 + 12\\\Delta = 16\\\\x = \frac{-b\pm \sqrt\Delta}{2a} = \frac{-(-2)\pm\sqrt{16}}{2 \cdot (-3)} = -\frac{2\pm4}{6}\\\\x_1 = -\frac{2+4}{6} = -\frac{6}{6} = -1\\\\x_2 = -\frac{2-4}{6} = \frac{2}{6}=\frac{1}{3}\\\\\boxed{S = \{-1; \ \frac 13\}}$