Question

3x²+12x+6=0 alguém ajuda?

Answer 1

a = 3
b = 12
c = 6
Δ = $12^{2} - 4 * 3 * 6 = 144 - 72 = 72$
$\frac{-12 +- \sqrt{72} }{2 * 3} = \frac{12+- \sqrt{72} }{6}$⇒$x_{1} = \frac{-12+ \sqrt{72} }{6}$⇒$x_{2} = \frac{-12 -\sqrt{72} }{6}$

Answer 2

Δ=B²-4AC

X=-B+-√Δ÷2A