Question

3x{x-2)=2(x+x/3} com a fórmula de bhaskara????

Answer 1

3x.{x - 2)=2.(x + x/3}
3x^2 - 6x = 2x + 2x/3
3x^2 - 6x - 2x - 2x/3 = 0
3x^2 - 8x - 2x/3 = 0
(3.3x^2 - 3.8x - 3.2x/3)/3 = 0/3
9x^2 - 24x - 6x = 0
9x^2 - 30x = 0
x.(9x - 30) = 0
x = 0
9x - 30=0
9x = 30
x = 30/9

R.: x = 0; x = 30/9