Question

(3X+4)²=?
(2X-3Y)²=
(5X+8) (5X-8)²=?

Answer 1

$(3x + 4)^{2} = (3x + 4) (3x + 4) = 9x^{2} + 24x + 16 \\ (2x - 3y)^{2} = 4x^{2} - 12xy + 9y^{2}$

$(5x +8) (5x - 8)^{2} = (5x + 8) (25x^{2} - 80x + 64)$
$125x^{3} - 200x^{2} - 640x + 832$