Question

3x+2y+z=10
x+2y+2z=11
x+y+z=6

Answer 1

3x+2y+z=10
3x+1(y+z)=10
3x=10-1(y+z)
x=10-y+z
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3

x+2y+2z=11
x+2(y+z)=11
x=11-2(y+z)
x=11-2z+2y


x+y+z=6
x+1(y+z)=6
x=6-y-z