Question

(3x-25) (5-2x) >0 me ajudemmmmmmmmmmmmm

Answer 1

(3x-25).(5-2x) > 0

15x - 6x² - 125 + 50x > 0

-6x² + 65x - 125 > 0

∆ = 65² - 4 . (-6) . (-125)

∆ = 4225 - 3000

∆ = 1225

x > - 65 +/- √1225 /2.(-6)

x > -65 +/- 35 /-12

x1 > -65 + 35 /-12

x1 > -30/-12

x1 > 2,5

x2 > -65 - 35 /-12

x2 > -100 /-12

x2 > 8,333...

S = {x∈R/x > 2,5 ou x > 8,333}