Question

3x-2
g
*
3-27
*+1
Me ajudem a resolver essa equação exponencial​

Answer 1

Olá,

${9}^{3x - 2} . {3}^{x} = {27}^{x + 1}$

$( {3}^{2} {)}^{3x - 2} . {3}^{x} = ( {3}^{3} {)}^{x + 1}$

${3}^{6x - 4} . {3}^{x} = {3}^{3x + 3}$

${3}^{6x} . {3}^{ - 4} . {3}^{x} = {3}^{3x} . {3}^{3}$

$\frac{ {3}^{6x + x} }{ {3}^{4} } = {3}^{3x} . {3}^{3}$

$\frac{ {3}^{7x} }{ {3}^{3x} } = {3}^{3} . {3}^{4}$

${3}^{4x} = {3}^{7}$

$4x = 7$

$x = \frac{7}{4}$