Question

3x^2=9x+12 Bhaskara equação 2°grau

Answer 1

$3 {x}^{2} - 9x - 12 = 0 \\ \\ x = \frac{ - ( - 9) + - \sqrt{( { - 9)}^{2} - 4 \times 3 \times ( - 12)} }{2 \times 3} \\ x = \frac{ + 9 + - \sqrt{81 + 144} }{6} \\ x = \frac{ + 9 + - \sqrt{225} }{6} \\ x = \frac{9 + - 15}{6} \\ x1 = \frac{9 + 15}{6} = \frac{24}{6} = 4 \\ x2 = \frac{9 - 15}{6} = \frac{ - 6}{6} = - 1$