Question

- 3x+2=7
3(x-4)+8=5
-2(y+4)=-10+9(y-1)
5(x-4)=-3+9(x-1)
-5(k-4)+4=2(-2k-2)

me ajudem​

Answer 1

Resposta:

A) $x=-\frac{5}{3}$

B) $x=3$

C) $y=1$

D) $x=-2$

E) $k=28$

Explicação passo a passo:

A) $-3x+2=7$

$-3x+2-2=7-2$

$-3x=5$

$\frac{-3x}{-3}=\frac{5}{-3}$

$x=-\frac{5}{3}$

B) $3\left(x-4\right)+8=5$

$3\left(x-4\right)+8-8=5-8$

$3\left(x-4\right)=-3$

$\frac{3\left(x-4\right)}{3}=\frac{-3}{3}$

$x-4=-1$

$x-4+4=-1+4$

$x=3$

C) $-2\left(y+4\right)=-10+9\left(y-1\right)$

$-2y-8=9y-19$

$-2y-8+8=9y-19+8$

$-2y=9y-11$

$-2y-9y=9y-11-9y$

$-11y=-11$

$\frac{-11y}{-11}=\frac{-11}{-11}$

$y=1$

D) $5\left(x-4\right)=-3+9\left(x-1\right)$

$5x-20=9x-12$

$5x-20+20=9x-12+20$

$5x=9x+8$

$5x-9x=9x+8-9x$

$-4x=8$

$\frac{-4x}{-4}=\frac{8}{-4}$

$x=-2$

E) $-5\left(k-4\right)+4=2\left(-2k-2\right)$

$-5k+24=-4k-4$

$-5k+24-24=-4k-4-24$

$-5k=-4k-28$

$-5k+4k=-4k-28+4k$

$-k=-28$

$\frac{-k}{-1}=\frac{-28}{-1}$

$k=28$