Question

(3x+2)²
(b+4)(b-4)
(a-2)²

Answer 1

1) (3x+2)²=
(3x+2) . (3x+2)=
9x²+6x+6x+4=
9x²+12x+4
2) (b+4) . (b-4)=
b²-4b+4b-16=
b²-16
3) (a-2)²=
(a-2) . (a-2)=
a²-2a-2a+4=
a²-4a+4
Espero ter ajudado

Answer 2

$(3x + 2)^2 \\ \\ (3x + 2)*(3x + 2) \\ \\ 9x^2 + 6x + 6x + 4 \\ \\ => 9x^2 + 12x + 4$

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$(b + 4)*(b - 4) \\ \\ b^2 - \not 4b + \not 4b - 16 \\ \\ => b^2 - 16$

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$(a - 2)^2 \\ \\ (a - 2)(a - 2) \\ \\ a^2 -2a - 2a + 4 \\ \\ => a^2 - 4a + 4$