Question

-3x^2+12x-12=0 alguem sabe responder???tem que tirar valor delta e tudo

Answer 1

-3x² +12x -12 = 0
-x² + 4x - 4 = 0

Δ = 4² -4(-1)(-4)
Δ = 16 - 16
Δ = 0

x = $\frac{-4+ \sqrt{0} }{2(-1)}$
x = $\frac{-4}{-2}$
x = 2