Question

√3x+1=5 ? Alguem mr ajuda pfvr?

Answer 1

Resposta a equacao nao tem solucao real

Explicação passo-a-passo:

se $\sqrt{3x} +1=5\\\sqrt{3x}=5-1\\\sqrt{3x} =4\\(\sqrt{3x})^{2}=16\\3x=16\\x=\frac{16}{3}$

Prova Real:

$\sqrt{3\frac{16}{3} }-1=5\\\sqrt{16} - 1 = 5?\\3\neq 5$

Answer 2

Resposta:

Explicação passo-a-passo:

$\sqrt{3x+1}=5\\\\(\sqrt{3x+1})^{2} =5^{2}\\\\3x+1=25\\\\3x=25-1\\\\3x=24\\\\x=\dfrac{24}{3}\\\\x=8\\\\\\Prova\\\\\sqrt{3.8+1}=5\\\\\sqrt{24+1}=5\\\\\sqrt{25}=5\\\\ok$