Question

3ab + 2ax + a, para a = –5, b = ⅔, x = 4/3 (R: -85/3

Answer 1

Resposta:

Olá bom dia!

Substituindo -5 no lugar de a, $\frac{2}{3}$ no lugar de b e $\frac{4}{3}$ no lugar de x:

$3.(-5).(\frac{2}{3} ) + 2.(-5).(\frac{4}{3}) + (-5)\\\\-10 - 10.(\frac{4}{3}) - 5\\\\-10 - 5 - \frac{40}{3} \\\\-15 - \frac{40}{3} \\\\\frac{-15.3-40}{3} \\\\\frac{-45-40}{3} \\\\-\frac{85}{3}$