Question

(3a2-27)/(3-a).(4a-12)/(2a2+12a+18)

Answer 1

[(3a²-27)/(3-a)] . [(4a+12)/(2a²+12a+18] =

{[3.(a²-9) / (3-a)]} . {[4(a+3) / 2(a²+6a+9)]} =

{[3.(a+3).(a-3)] / (3-a)]} . {2(a+3) / (a+3)²} =

{[3.(a+3).(-1)]} . {2/(a+3)} =

{-3.(a+3)} . {2 / (a+3)} = -3.2 = -6