Question

3a+4b,para a=4 eb=-1 _________
a^{2}+ab+b^{2},para a=-1 eb=-2 _________
(x+y^{2})/3,para x=2 e y=2 __________

Me ajudem

Answer 1

a = 4; b = - 1

= 3a + 4b
= 3.4 + 4.(-1)
= 12 - 4
= 8
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a = - 1; b = - 2
= a² + ab + b²
= (-1)² + (-1).(-2) + (-2)²
= 1 + 2 + 4
= 3 + 4
= 7