Question

3a+2c=1
a+c=0


3b+2d=0
b+d=1​

Answer 1

3a+2c=1
a+c=0(*-2)—>3a+2c=1 e -2a-2c=0
Somando tudo fica:
a=1
então se a+b=0
b=-1


3b+2d=0
b+d=1 (*-2)

3b+2d=0
-2b-2d=-2
b=-2
então se b+d=1
d=1+2=3