Question

(3a-1)² qual a resposta mim ajudem ai

Answer 1

Desenvolvendo o binômio, temos:

$(3a-1)^2~=\\\\\\=~(3a-1)~.~(3a-1)\\\\\\Aplicando~a~propriedade~distributiva~da~multiplicacao\\\\\\=~3a~.~3a~+~3a~.~(-1)~-~1~.~3a~-~1~.~(-1)\\\\\\=~9a^2~-~3a~-~3a~+~1\\\\\\=~\boxed{9a^2-6a+1}$