Question

(39-24÷4×3)÷7+[(6+5×3)-(9²-7×3)×3]⁵​

Answer 1

Resposta:

(39-24÷4×3)÷7+[(6+5×3)-(9²-7×3)×3]⁵​

($39-24\div \:4\times \:3$ )÷7+[(6+5×3)-(9²-7×3)×3]⁵​

(39-6 x 3)÷7+[(6+5×3)-(9²-7×3)×3]⁵​

(39-18)÷7+[(6+5×3)-(9²-7×3)×3]⁵

​$=21\div \:7+\left[\left(6+5\times \:3\right)-\left(9^2-7\times \:3\right)\times \:3\right]^5$

=21÷ 7 +[(6+5×3)-(9²-7×3)×3]⁵

=21÷ 7 +[(21)-(9²-7×3)×3]⁵

=21÷ 7 +[(21)-(81-21)×3]⁵

=21÷ 7 +[(21)-(60×3]⁵

=21÷ 7 +[(21)-(180]⁵

=21÷ 7 +[(21-180]⁵

=21÷ 7 +[-159]⁵

=21÷ 7 +[-101621504799]

=21÷ 7 -101621504799

= 3 -101621504799

= -101621504796

Explicação passo-a-passo:

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